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javaScript Method chaining tutorial ( function chaining)
- January 30, 2024
- Posted by: MainInstructor
- Category: JavaScript
Video Title: javaScript Method chaining tutorial ( function chaining)
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Simply superb ☺️
What is difference in defining a variable like $url or var url in js
hi, how to limit method chain to some perticular function ? returning this will give all method access, and i am trying to make a routing package where i need to return a chain of method like router.get() here i only want to return get, post and other method but i have many methods in class that all are showing up, i also have applyMiddleware() method that i only want after method is selected but it is showing while accessing router.* anything
Is it possible to chain methods from factory functions? E.g. sayName().location().favFoods(). I can't use the `return this` keyword inside the factory function like how you would with a regular constructor function 🙁
const nerd = (user, city, food) => {
const { sayName, location } = Person(user, city)
const { favFoods } = FaveFood(food, user) //<- can also use parameter inside other constructors
const doSOmethingNerdy = () => console.log(`${user} likes nerd stuff!`)
return { sayName, location, favFoods, doSOmethingNerdy }
<!> return this <not applicable 🙁 >
}
This man is the best teacher, YouTube has been recommending the wrong people to me
Anyone Here to know how Promise.then().catch() chained together ?
This is a topic that's been on my mind for some time now, I've read blogs about method chaining but never quite understand it. Watching this video now makes me understand it better. Thanks
Why not just write a class instead of an object that acts as a class? Why in good heavens does Javascript even give you the option to do this?
Calling both variables "i" is kinda misleading.
one question, please is it correct to do the following code?
var obj = function () {
var oper = {
i: 0,
add: function (j) {
this.i += j
return this
},
sub: function (j) {
this.i -= j
return this
},
print: function () {
console.log(this.i)
},
}
return oper
}
var x = obj() //no need new
x.add(3).sub(2).print() //1
console.log(x)
I hope your answer, thank you. Blessings
so function xpressions inside a function expression
The only video I understood.
thanks for this tutorial.
x.add(3) is fine when we call it, why undefined ? inside the console.log?
I just wish the keyboard clicks could be louder…
Great tutorial, but “substract”??
Method chaining on closure is bit tough to understand for me
I have never found most precise, concise and trick catching instructive series on YouTube or Udemy like this, really good baked pastry been brought only by "bakers". If you would author a book on JS it will be of most useful one
How can I do this asyncronously?
What is the logic behind return this; after you made 'i' as private variable?
When you write this.i += i inside this.add func() why it isn't creating a new this? I thought only arrow func doesn't have their own this
Return this is instant object, what is value hold by this element, it is difficult to understand
Subtract*
Nice explanation sir.. I have one doubt is that what is difference between creating object with new and without new operator because which i know (if i am wrong then rectify me) that while creating an object with new operator they maintain there own data member & method then i tied with above example without using new operator i was thinking that may be they are referring to same address/reference
Without Using new Operator
var x = obj();
var y = obj();
console.log(x===y) // false
x.add(3).substract(2).substract(2).print(); // -1
y.add(3).substract(2).print(); // 1
With Using new Operator
var x = new obj();
var y = new obj();
console.log(x===y) // false
x.add(3).substract(2).substract(2).print(); // -1
y.add(3).substract(2).print(); // 1
can you help me to clear my this doubt..Thanks
Kamaal karte ho Patel ji
so, all this 2 examples are working, so I can use any of them?
Nice lesson, thank you for teaching, keep up the good work, peace!
when we should use 'new' keyword and should not , please help me to understand this
The best one
jillakidumma
Note the shorthand instead of "{add: add, substract: substract, print: print};" you can now write
return {add, substract, print}; And thanks for this clear demonstration.
Hi, I liked your tutorial. Is there other way than just return{add:add, substract:st…} and why didn't you use new obj()??? Could you please guide me 🙂
very nice
Very nice explanation.. hurray👏👏
javaScript Method chaining tutorial ( function chaining) what you want to explain in this video did get it please tell me
this guy is on point! great teacher
Hi, I have tried in my localhost, but i didn't get any console output, please guide me
very nice explanation.
You are very good at explaining things.
why return "this" ?
Thanks great explanation, easy to follow
i must very interesting tutorials , you simply made it so easy to understand ,thanks a lot
really helpful, nice one
are bhai substract nahi, Subtract 🙂
awesome sir..your advanced js tutorial
This is very helpful, thanks for sharing your knowledge!
i dont understand how come you were able to get the correct result here 04:45 but when you chain them you had to return the object first ???